Tan inverse 1+cosx/sinx
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Tan inverse 1+cosx/sinx
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WebSolution Let y = tan - 1 ( 1 + cos x) sin x Then ⇒ y = tan - 1 ( 2 cos 2 x 2 2 sin x 2, cos x 2) ⇒ y = tan - 1 ( cot x 2) ⇒ y = tan - 1 { tan ( π 2 - x 2) } ⇒ y = π 2 - π 2 ∴ d y d x = 0 - 1 2 = - 1 2 Concept: Derivatives of Inverse Trigonometric Functions Report Error Is there an error in this question or solution? 2024-2024 (March) Delhi Set 1 WebDec 27, 2024 · Find the derivative of `tan^(-1)((cosx - sinx)/(cosx + sinx))` with respect to \\'x\\'jee mains 2024, jee main january, class 12, jee main maths, jee 2024, cbs...
WebHow can we solve tan inverse (cos x /1-sinx)? taninverse (cosx/ (1 - sinx)) =taninverse ( (cos (pi/2) + cosx)/ (sin (pi/2) - sinx)) = taninverse ( (2cos (pi/4 + x/2)cos (pi/4 - x/2))/ (2cos (pi/4 + x/2)sin (pi/4 - x/2))) =taninverse ( (cos (pi/4 - x/2))/ (sin (pi/4 - x/2))) =taninverse (cot (pi/4 - x/2)) = taninverse (tan (pi/4+ x/2)) = pi/4+ x/2 2 WebTrigonometry. Trigonometry (from Ancient Greek τρίγωνον (trígōnon) 'triangle', and μέτρον (métron) 'measure') is a branch of mathematics concerned with relationships between angles and ratios of lengths. The field emerged in the Hellenistic world during the 3rd century BC from applications of geometry to astronomical studies.
WebSolution The correct option is A 1 Differentiate with respect to X L e t y = tan - 1 ( cos x + sin x) ( cos x – sin x) = tan - 1 ( 1 + tan x) ( 1 – tan x) = tan - 1 ( tan π 4 + tan x) ( tan π 4 – tan π 4 tan x) = tan - 1 tan ( π 4 + x) = ( π 4 + x) d y d x = 0 + 1 = 1 Hence, Differentiation of tan - 1 ( cos x + sin x ( cos x - sin x)) w.r.t X is 1. WebPet Adoption - Search dogs or cats near you. Adopt a Pet Today. Pictures of dogs and cats who need a home. Search by breed, age, size and color. Adopt a dog, Adopt a cat.
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