WebbHe used the correspondence principle to associate the orbital energy to the lines radiated at long wavelengths. (3) The observed spectral lines were photons emitted as the electron descended from an upper orbit to a lower orbit. Since the lines were discrete only certain orbits were stable (or allowed). He postulated that (4) orbits with ... Webb14 dec. 2015 · The core is the only part of the sun that produces an appreciable amount of heat through fusion. In fact, 99% of the energy produced by the sun takes place within 24% of the sun's radius. By 30% ...
Momentum conservation with photons - Physics Stack Exchange
WebbThe photon radiated from hydrogen corresponding to 2nd line of Lyman series is absorbed by a hydrogen like atom ‚X™ in 2 nd excited state. As a result the hydrogen like atom ‚X™ makes a transition to n th orbit. WebbTranscribed Image Text: (4) (a) How many microns is the wavelength of a photon radiated by a hydrogen atom in which the electron jumps from the n = 5 orbit to the n = 6 orbit? (b) The Sun has a temperature of 5770 K, and radiates a thermal spectrum. How many nanometers (nm) is the wavelength of its maximum intensity? fun things that start with j
Answered: Q3. An electron in an atom which is… bartleby
Webb7 juli 2024 · The curve 1, which is shown with the dotted line, is the initial wavelength distribution of the photons directly emitted from the Sun. This curve corresponds to the black-body radiation in case of a temperature of T = 6000\, {\text {K}} for the sun obtained from Planck’s law shown in Eq. ( 2.5) in the next section. Webb25 mars 2024 · The boundary conditions for the modeling used were hydrogen plasma with carbon as the only impurity species at a total heating power of 4.5 MW and a radiated power of carbon of 1 MW. Cross-field particle diffusivity of 0.5 m 2 s −1 for both, hydrogen and carbon ions, with a cross-field heat conductivity for both electrons and ions of 0.75 … Webb11 juli 2014 · The formula is E = hc λ or λ = hc E, where h is Planck's constant. For example, what is the wavelength of a photon that has an energy of 3.36 × 10⁻¹⁹ J? λ = hc E = 6.626 ×10⁻³⁴J⋅s ×2.998 × 10⁸m⋅s⁻¹ 3.36 × 10⁻¹⁹J = 5.91 × 10⁻⁷ m = 591 nm Answer link fun things to add to a stream